NEON NUMBER PROGRAM IN C

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 In this example , you will learn a program to check whether entered number is Neon number or  not.

Neon Number:

Neon number is the number whose sum of digits of square of number is equal to the number itself.

Lets consider one example, 

suppose we want to check whether 9 is neon number or not.

9² = 81

and sum of digits of 81 = 8+1 = 9

i.e. the number itself.

Thus, 9 is a neon number.


Program:

//Program to check whether given number is Neon number or not

#include <stdio.h>
int main( )
{
int num, rem, sq, sum=0;
printf("Enter any number:");
scanf("%d",&num);
sq=num*num;
              
    while(sq !=0)
    {
         rem= sq%10;
         sum=sum +rem;
         num=num/10;
     } 
          
    if(sum==num)
    {
        printf("%d is a neon number",num);
     }
   else
    {
    printf("%d is not a neon number",num);
    }

return 0;
}


Output: 

Enter the number: 9
9 is Neon number


Enter the number:85
85 is not a Neon number


So that's it ! Just try this code by your own. If you have any doubts then feel free to drop a comment . I'll be happy to answer your questions .

Keep coding....

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